Questions Data-Management-Foundations Pdf, Exam Data-Management-Foundations Objectives

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Exam Data-Management-Foundations Objectives & Data-Management-Foundations Dump Check

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WGU Data Management – Foundations Exam Sample Questions (Q14-Q19):

NEW QUESTION # 14
Which database operation locates the needed table blocks?

A. Binary search
B. Index scan
C. Table scan
D. Fan-out

Answer: B

Explanation:
Anindex scanis a database operation thatquickly locates table blocksusing anindexrather than scanning the entire table. It significantly improves query performance.
Example Usage:
sql
SELECT * FROM Employees WHERE EmployeeID = 105;
* If EmployeeID isindexed, the database uses anindex scantoquickly find the record.
Why Other Options Are Incorrect:
* Option A (Binary search) (Incorrect):A searching algorithm, but not a database operation.
* Option B (Table scan) (Incorrect):Scans theentire table, which isslowerthan an index scan.
* Option C (Fan-out) (Incorrect):Refers tobranching in B-Treesbut doesnot locate table blocks directly.
Thus, the correct answer isIndex scan, as it efficiently locates table blocks.

NEW QUESTION # 15
Which main characteristic is used to differentiate between strong and weak entities in the process of database design?

A. Foreign key
B. Cardinality
C. Primary key
D. Association

Answer: C

Explanation:
Indatabase design, an entity is classified asstrong or weakbased on whether it has aprimary keythat uniquely identifies its records.
Differences Between Strong and Weak Entities:

CREATE TABLE Orders (
OrderID INT PRIMARY KEY,
CustomerID INT
);
CREATE TABLE OrderDetails (
OrderDetailID INT,
OrderID INT,
ProductID INT,
PRIMARY KEY (OrderDetailID, OrderID),
FOREIGN KEY (OrderID) REFERENCES Orders(OrderID)
);
* Orders is astrong entity(has OrderID as its own primary key).
* OrderDetails is aweak entity(depends on OrderID for uniqueness).
Why Other Options Are Incorrect:
* Option A (Association) (Incorrect):Associations describerelationshipsbut do not define strong/weak entities.
* Option C (Foreign key) (Incorrect):Weak entitiesdepend on foreign keys, butprimary keysdefine their status.
* Option D (Cardinality) (Incorrect):Cardinality definesrelationship constraintsbut doesnot differentiate entity types.
Thus, the correct answer isPrimary key, as it is the defining characteristic betweenstrong and weak entities.

NEW QUESTION # 16
How is the primary key indicated in a table?

A. By using an SQL keyword
B. By using bold typeface in the appropriate column
C. By using a diamond symbol inserted into the table
D. By using a formula in SQL

Answer: A

Explanation:
In SQL, aprimary key is explicitly defined using the PRIMARY KEY keywordwhen creating a table.
Example Usage:
sql
CREATE TABLE Products (
ProductID INT PRIMARY KEY,
Name VARCHAR(100),
Price DECIMAL(10,2)
);
* Here,PRIMARY KEY is the SQL keyword that designates ProductID as the primary key.
Why Other Options Are Incorrect:
* Option A (Formula in SQL) (Incorrect):SQLdoes not use formulas to define primary keys.
* Option C (Bold typeface) (Incorrect):SQL syntax does not rely on text formatting.
* Option D (Diamond symbol) (Incorrect):ER diagramsmight use symbols, but SQLdoes not use diamonds to indicate keys.
Thus, the correct answer isSQL keyword, as primary keys are explicitly defined using PRIMARY KEY.

NEW QUESTION # 17
What is the last step in the logical design process for designing a database?

A. Analyze data requirements
B. Discover entities
C. Determine cardinality
D. Apply a normal form

Answer: D

Explanation:
Thelogical design phasein database development focuses onstructuring data efficientlyto eliminate redundancy and ensure integrity. Thefinal step in logical designis toapply normalization (normal forms)to optimize the database schema.
Steps in Logical Database Design:
* Discover entities# Identify real-world objects (e.g., Customers, Orders).
* Determine cardinality# Define relationships between entities (one-to-one, one-to-many).
* Analyze data requirements# Determine the attributes each entity needs.
* Apply normal forms# Eliminate redundancy and improve data consistency.
Example Usage:
* After identifying entities likeStudentsandCourses, applying3rd Normal Form (3NF)ensures that data isorganized without redundancy.
Why Other Options Are Incorrect:
* Option A (Analyze data requirements) (Incorrect):Doneearlierto define attributes.
* Option C (Determine cardinality) (Incorrect):Donebeforenormalization to establish relationships.
* Option D (Discover entities) (Incorrect):Done at thebeginningof database design.
Thus, the correct answer isApply a normal form, as normalization is thelast step in logicaldesign.

NEW QUESTION # 18
Which command is used to filter group results generated by the GROUP BY clause?

A. REPLACE
B. WITH
C. WHERE
D. HAVING

Answer: D

Explanation:
TheHAVINGclause is used in SQL to filtergrouped resultsgenerated by the GROUP BY clause. Unlike WHERE, which filters individual rowsbeforegrouping, HAVING filtersafter aggregationhas been performed.
Example Usage:
sql
SELECT Department, AVG(Salary) AS AvgSalary
FROM Employees
GROUP BY Department
HAVING AVG(Salary) > 50000;
* This query first groups employees by Department, calculates theaverage salary per department, and then filters onlythose departments where the average salary is greater than 50,000.
Why Other Options Are Incorrect:
* Option A (REPLACE) (Incorrect):Used for string substitution, not filtering.
* Option C (WITH) (Incorrect):Used inCommon Table Expressions (CTEs), not for filtering.
* Option D (WHERE) (Incorrect):Used forrow-level filtering before aggregation, but itcannot be used on aggregate functions like SUM() or AVG().
Thus,HAVING is the correct answerfor filtering after grouping.

NEW QUESTION # 19
......

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Questions Data-Management-Foundations Pdf, Exam Data-Management-Foundations Objectives

Exam Data-Management-Foundations Objectives & Data-Management-Foundations Dump Check

WGU Data Management – Foundations Exam Sample Questions (Q14-Q19):

Prepare With WGU Data-Management-Foundations Exam Questions [2025] A Genuine Information For You

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